A 60.0 kilogram person will need to climb a 10.0 m stairway how many times to "work off" each excess Cal (kcal) consumed? Please show work

The calorie used by dieticians is a kilocalorie. One kilocalorie is equal to 4,184 joules of energy.

Since W (work) = Fd and the force is equal to the weight (mass x gravity) of the person, W = mgh** (mass x gravity x height).

Plug in the values: (60kg) (constant gravity: 9.81 m/s²) (10 m) = 5886 J

This question doesn't have the given the number of excess calories.

But anyway, each climb will burn off 1.4 Calories (5886 J / 4184 J).

If the person consumed 100 Calories, a total of 71.4 (100 cal/ 1.4 cal) trips up the stair are needed to use all the energy excess energy.

Tags: caloriekgenergy